Bernoulli's Equation & Continuity — Detailed formulas, worked example and calculator
1) Fundamental formulas
Bernoulli (along a streamline, inviscid, steady):
$$\frac{P_1}{\rho g} \;+\; \frac{v_1^2}{2g} \;+\; h_1 \;=\; \frac{P_2}{\rho g} \;+\; \frac{v_2^2}{2g} \;+\; h_2$$
Continuity (incompressible):
$$Q = v_1 A_1 = v_2 A_2 \quad\text{with}\quad A=\frac{\pi d^2}{4}$$
$$\Rightarrow v_1 d_1^2 = v_2 d_2^2 \quad(\text{if circular pipe and same fluid})$$
Derived useful rearrangement (solve for \(P_2\))
From Bernoulli:
$$\frac{P_1}{\rho g}+\frac{v_1^2}{2g}+h_1=\frac{P_2}{\rho g}+\frac{v_2^2}{2g}+h_2$$
Multiply by \(\rho g\) and rearrange:
$$\boxed{P_2 = P_1 + \tfrac{1}{2}\rho\,(v_1^2 - v_2^2) + \rho g\,(h_1 - h_2)}$$
(This is the form used to compute pressure at point 2 given known \(P_1, v_1, v_2, h_1, h_2\).)
2) Inputs (change and press Compute)
Units: diameters in m, pressures in Pa (use 1e5 for 100 kPa), velocities in m/s, heights in m, density kg/m³, g m/s².
Quick results
Detailed step-by-step solution
Notes
- Bernoulli here neglects head loss (no friction) and assumes steady, incompressible flow along a streamline.
- If pipes have roughness/viscous losses, include head loss term \(h_L\) on RHS: add \(+h_L\) where appropriate.
- Pressures used above are absolute or gauge consistently. If P₁ is gauge and P₂ returned is absolute minus same atmospheric value—treat consistently.
Worked numerical example (with the values shown initially)
Given:
- \(d_1 = 0.100\ \mathrm{m},\ d_2=0.050\ \mathrm{m}\)
- \(v_1 = 2.00\ \mathrm{m/s}\)
- \(P_1 = 200{,}000\ \mathrm{Pa}\) (200 kPa)
- \(h_1 = 0.0\ \mathrm{m},\ h_2 = 1.5\ \mathrm{m}\)
- \(\rho = 1000\ \mathrm{kg/m^3},\ g = 9.81\ \mathrm{m/s^2}\)
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